SURVEY .

Using the definitions for equivalent resistance for resistors in parallel, we can analyze some circuits with these setups.

Two ohmic resistors (\(R_1\) and \(R_2\)) are connected in parallel with a cell. A CD player with a resistance of 40 ohms has a 2.)

light with a resistance of 2200 ohms. Question 1 . The current through the \(\text{12}\) \(\Omega\) resistor is \(\text{1.5}\) \(\text{A}\). Calculate the current (I) in this circuit if the resistors are both ohmic in nature. equation by R.

What is the minimum wattage of electric heater?

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through the strobe light?

There are however two resistors in the circuit and we need to find the total resistance. Electric power and DC circuits. electrical heaters are a continuous load so total connected load be 80% of circuit rating, Total allowable wattage = 3600 * 0.8 = 2880 Watts.

A nine volt battery supplies power to a cordless

Since the resistors are ohmic and we are given the voltage across the cell and the current through the cell, we can use Ohm’s Law to find the equivalent resistance in the circuit.\begin{align*}R & = \frac{V}{I} \\& = \frac{9}{\text{4.8}} \\& = \text{1.875} \ \Omega\end{align*}, Since we know the equivalent resistance and the resistance of \(R_1\), we can use the formula for resistors in parallel to find the resistance of \(R_2\).\begin{align*}\frac{1}{R} & = \frac{1}{R_1} + \frac{1}{R_2}\end{align*}Rearranging to solve for \(R_2\):\begin{align*}\frac{1}{R_2} & = \frac{1}{R} – \frac{1}{R_1} \\& = \frac{1}{\text{1.875}} – \frac{1}{3}\\& = \text{0.2} \\R_2 & = \frac{1}{\text{0.2}} \\& = \text{5} \ \Omega\end{align*}, The resistance \(R_2\) is \(\text{5}\) \(\Omega\). If a single phase circuit feeding residential electric heaters, what is the maximum allowable wattage that can be connected?

Tags: Question 6 . Since the resistors are connected in parallel, the total (equivalent) resistance R is: \[\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}}.\]\begin{align*} \frac{1}{R} &= \frac{1}{R_1} + \frac{1}{R_2} \\ &= \frac{1}{2} + \frac{1}{4} \\ &= \frac{2+1}{4} \\ &= \frac{3}{4} \\ \text{Therefore. } Khan Academy is a 501(c)(3) nonprofit organization. for the Learning Technologies Project, We have been given the potential difference across the cell and the resistances of the resistors, so we can use Ohm’s Law to calculate the current. An 18 volt cell is connected to two parallel resistors of \(\text{4}\) \(\Omega\) and \(\text{12}\) \(\Omega\) respectively.

Ohm’s Law Practice Problems. The Following Section consists of Multiple Choice Questions on Ohm’s Law.

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answer choices . This activity was created by Steven Gutierrez, If the voltage is doubled, the current in the circuit ………….. A 6 AWG THHN conductor is good for use for how many KW of load at 120 volts? Since the resistors are ohmic in nature, we can use Ohm’s Law. Space Administration. Your email address will not be published. curling iron with a resistance of 18 ohms. 30 seconds . Sketch the circuit diagram

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A 120 volt circuit which has a resistance of 12 ohms draws a current of 10 A. A 110 volt wall outlet supplies power to a strobe The current through the \(\text{4}\) \(\Omega\) resistor is \(\text{4.5}\) \(\text{A}\). at the NASA Glenn Research Center, in 1996. Consider a circuit consisting of a single cell and three resistors that are connected in parallel.

This is a lesson from the tutorial, Electric Circuits and you are encouraged to log in or register, so that you can track your progress. R &= \text{1.33} \Omega\end{align*}, \begin{align*} R&= \frac{V}{I} \\ R \cdot \frac{I}{R} &= \frac{V}{I} \cdot \frac{I}{R} \\ I &= \frac{V}{R}\\ I &= V \cdot \frac{1}{R}\\ &= (12) \left(\frac{3}{4}\right) \\ &= \text{9}\text{ A}\end{align*}. We need to calculate the resistance \(R_2\). and calculate how many volts supply the CD player?

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